Matematické Fórum

stuart clark

If $(1+x+x^2)^n = \binom{n}{0}+\binom{n}{1}x+\binom{n}{2}x^2\cdots \cdots$

Then $\binom{n}{0}\binom{n}{1}-\binom{n}{1}\binom{n}{2}+\binom{n}{2}\binom{n}{3}+\cdots \cdots$

and $\binom{n}{0}\binom{n}{2}-\binom{n}{1}\binom{n}{3}+\cdots \cdots$

laszky · 10. 02. 2018 23:23

The statement is formulated in a strange way ...there isnt any equality.

Matematické Fórum

#1 19. 01. 2018 14:46 — Editoval stuart clark (19. 01. 2018 14:50)

Binomial sum

#2 10. 02. 2018 23:23

Re: Binomial sum

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