Matematické Fórum

stuart clark · 02. 05. 2015 08:47

No. of zeros immediately following decimal part in $(0.02)^{26}$

Brano · 09. 05. 2015 11:14 — Editoval Brano (24. 05. 2015 12:26)

the key is to estimate $2^{26}$ . one can remember that $2^6=64$ and $2^{10}=1024$ so convince yourself that $10^7<2^{26}<10^8$ therefore $10^{7-52}<0.02^{26}<10^{8-52}$ or $0.1<10^{44}\cdot 0.02^{26}<1$ so the answer to your question is $44$ .

stuart clark · 11. 07. 2015 12:50

Thanks ↑ Brano:

Matematické Fórum

#1 02. 05. 2015 08:47

no. of zeros.

#2 09. 05. 2015 11:14 — Editoval Brano (24. 05. 2015 12:26)

Re: no. of zeros.

#3 11. 07. 2015 12:50

Re: no. of zeros.

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