Matematické Fórum

cx^2+x+1 > 0

a) c = 0
x>-1

D = 1- 4c

b) D > 0

c < 1/4

b1)
0 < c < 1/4

x ∈ (-∞, (-1-sqrt(1-4c))/2c) ∪ ((-1+sqrt(1-4c))/2c), ∞)

b2)

c ∈ (-∞, 0)

x ∈ ((-1-sqrt(1-4c))/2c), ((-1+sqrt(1-4c))/2c))

c) D = 0
c = 1/4
x ∈ ∅

d) D < 0
c > 1/4
x ∈ R

Je to, prosím, takhle ok?