↑ stuart clark:
The problem can be solved as follows ...
Skrytý text:Step 1. Let

denotes the real number for which

We know that the auxilliary function

is a continuos increasing function with

and

as

. Hence there exists exactly one real number

for which the above equality holds true. Moreover, one can easily deduce that

.
Step 2. Next, we transform the equality as follows

where

is a sufficiently large positive integer s.t. both terms on the left hand side are positive. Now, computing the tangent of the left and right hand side gives

For the numerator on the left hand side we conclude that

a finite value, whereas the limit of the right hand side is

This indicates that the denominator on the left hand side satisfies

which implies the equality
Step 3. In the next step we use known formulas

and

We apply this formulas to transform the identity above
After simplifications we obtain the biquadratic equation

Solving this equation under the restrictive condition

we get the final answer, i.e.,
Remark. Note that the problem can be stated equivalently in a more difficult modification as

because of
