(finite).
and 
#2 26. 07. 2011 15:59 — Editoval Rumburak (27. 07. 2011 11:00)
Re: limita.
and 
. We can use 
(binomic serie), 
(geometric serie) . ![$\frac{1}{\sqrt{1+x^2}}-\frac{1+ax}{1+bx} = \sum_{k=0}^{\infty}{ {-\frac{1}{2}} \choose k}x^{2k} - (1 + ax)\sum_{k=0}^{\infty}(-bx)^k =\\= \sum_{k=1}^{\infty}{ {-\frac{1}{2}} \choose k}x^{2k} - \sum_{k=1}^{\infty}(-bx)^k -ax\sum_{k=0}^{\infty}(-bx)^k=\\=\sum_{k=1}^{\infty}{ {-\frac{1}{2}} \choose k}x^{2k} - \sum_{k=1}^{\infty}\left[(-bx)^{k} + ax(-bx)^{k-1}\right] =\\= \sum_{k=1}^{\infty}{ {-\frac{1}{2}} \choose k}x^{2k} - \sum_{k=1}^{\infty}(-b)^{k-1}\left(-b +a\right) x^k$](/mathtex/51/51d5fde0db14fa61b0731d9cbbfdc46d.gif "kopírovat do textarea")
.
, 
when 
, 
when 
, 
when 
.
satisfying (0) do not exist. Offline
#3 10. 10. 2011 22:49 — Editoval Pavel (10. 10. 2011 22:53)
Re: limita.
↑ Rumburak:
The limit can be found in elementary way:
has to hold. So be it. Then
and 
.Backslash je v TeXu tak důležitý jako nekonečno při dělení nulou v tělesech charakteristiky 0.
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#4 11. 10. 2011 05:07
#6 11. 10. 2011 14:52 — Editoval vanok (23. 10. 2011 13:34)
Re: limita.
and 
are 0.
and 
Srdecne Vanok
The respect, the politeness are essential qualities...and also the willingness.
Do not judge the other one.
Ak odpovedam na nejaku otazku. MOJ PRINCIP NIE JE DAT ODPOVED ALE UKAZAT AKO SA K ODPOVEDI DOSTAT
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#7 23. 10. 2011 11:07
Re: limita.
↑ vanok:
question: what is your opinion concerning my solution?
Srdecne Vanok
The respect, the politeness are essential qualities...and also the willingness.
Do not judge the other one.
Ak odpovedam na nejaku otazku. MOJ PRINCIP NIE JE DAT ODPOVED ALE UKAZAT AKO SA K ODPOVEDI DOSTAT
Offline