Matematické Fórum

stuart clark · 18. 12. 2011 13:44

If $A$ and $B$ are two events such that $P(A)=\frac{3}{5}$ and $P(B) = \frac{2}{3}$

Then

$(i)\;\; P(A\cap B)\in$

$(ii)\;\; P(A\cup B)\in$

$(iii)\;\; P\left(\frac{A}{B}\right)\in$

$(iv)\;\; P\left(\frac{B}{A}\right)\in$

check_drummer · 18. 12. 2011 18:22

I will answer only (i), other points are similar:

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stuart clark · 20. 12. 2011 11:51

thanks check_drummer

can you explain me the answer

check_drummer · 20. 12. 2011 20:47

↑ stuart clark:
I tried to find "best" and "worst" cases - i.e. A,B can be seen as a subsets of I:=<0;1> interval and we are trying to find such sets A,B of given measures that has the biggest and least measure of intersect - the biggest intersect is when A is part of B, i.e. measure is 3/5 and the least intersect is when A and B cover I completely, then the measure of intersect is 4/15. I hope there is no problem with "unmesurable" sets.

stuart clark · 21. 12. 2011 20:17

thank check_drummer

but how can i calculate $P(A\cup B)$

check_drummer · 21. 12. 2011 22:28

↑ stuart clark:
In the same manner - find worst case and best case...

Matematické Fórum

#1 18. 12. 2011 13:44

probability

#2 18. 12. 2011 18:22

Re: probability

#3 20. 12. 2011 11:51

Re: probability

#4 20. 12. 2011 20:47

Re: probability

#5 21. 12. 2011 20:17

Re: probability

#6 21. 12. 2011 22:28

Re: probability

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