Matematické Fórum

xxxblooondexxx · 26. 05. 2009 09:08

Poradil by mi nekdo moc prosim vazne sem vkoncich dekuju moc:-)

-\sqrt{676}

4\sqrt{150}

\frac{2}{3}\sqrt{243}

\pm\sqrt{0,0256}

\sqrt{\frac{49}{900}}

Cheop · 26. 05. 2009 09:14 — Editoval Cheop (26. 05. 2009 09:25)

↑ xxxblooondexxx:
$26^2=676\,\Rightarrow\nl-\sqrt{676}=-26$
$\frac{4}{\sqrt{150}}=\frac{4}{\sqrt{25\cdot 6}}=\frac 45\cdot\frac{1}{\sqrt 6}=\frac 45\cdot\frac{\sqrt 6}{6}=\frac{2\sqrt 6}{15}$
$4\sqrt{150}=4\cdot 5\sqrt 6=20\sqrt 6$
$\frac 23\sqrt{243}=\frac 23\sqrt{3\cdot 81}=\frac 23\cdot 9\sqrt 3=6\sqrt 3$