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#1 06. 11. 2019 10:55

stuart clark
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Complex Number

Let $A(z_{1}),B(z_{2}),C(Z_{3})$ and $D(z_{4})$ are the vertices of an Trepezium in an Argand plane

Let $|z_{1}-z_{2}|=4,|z_{3}-z_{4}|=10$ and Diagonal $AC$ and $BD$ intersect

at $P.$ It is given that $\displaystyle \arg\bigg(\frac{z_{4}-z_{2}}{z_{3}-z_{1}}\bigg)=\frac{\pi}{2}$ and $\displaystyle \arg\bigg(\frac{z_{3}-z_{2}}{z_{4}-z_{1}}=\frac{\pi}{4}\bigg).$

Then area of Triangle $\displaystyle PCB$ and $|CP-DP|$ is

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