↑ _NanoP_:
Ahoj, jedna se o derivaci soucinu funkci. Pouzije se vzorecek [mathjax] (fg)'=fg'+f'g[/mathjax]:
[mathjax] {\displaystyle \frac{d}{dx} \left(\left(1-x^2\right)\frac{dP}{dx}\right) = \left(1-x^2\right)\frac{d}{dx}\left(\frac{dP}{dx}\right) + \frac{d}{dx}(1-x^2)\frac{dP}{dx} = \left(1-x^2\right)\frac{d^2P}{dx^2} -2x\frac{dP}{dx} } [/mathjax]
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