#3 08. 12. 2010 19:47
Re: Definiční obory logaritmické fce
↑ manolka: zdravim, ano postup by mal byt spravny az na ten posledny krok. spravme kontrolu x <1 zoberieme napr -7 je to mensie ako 1 ? ano je dosadime (1+(-7)(1-(-7)=(-6)(8)=-48 a to je zaporne. posledny krok nie je spravny treba uvazovat kedy je x^2 < 1 ?? spravime si pomocnu rovnicu x^2=1 tato ma dva korene 1 a -1 to su nulove body teda mame intervaly (-inf;-1) (-1;1) (1;inf) postupne overte kazdy interval v ktorom je x^2<1 a dostanete vysledok
"If you think you understand quantum mechanics, you don't understand quantum mechanics" - Richard Feynman
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#5 08. 12. 2010 20:31
Re: Definiční obory logaritmické fce
↑ manolka: ano interval mate spravne
"If you think you understand quantum mechanics, you don't understand quantum mechanics" - Richard Feynman
"Linux is like a tepee no windows, no Gates, apache inside"
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